问题描述
试图在 .ajax() 使用 .find().不幸的是，alert(result) 不返回 div#result.
这是我的代码:
$.ajax({网址:网址，缓存:假，成功:功能(响应){结果 = $(response).find("#result");警报(响应)；//按预期工作(返回所有 html)警报(结果)；//返回 [object 对象]}});具体回答您的问题，它似乎工作正常.您说它返回 [object Object]，这就是 jQuery 使用 find("#result") 方法返回的内容.它返回一个匹配 find 查询的 jQuery 元素.
尝试获取该对象的属性，例如 result.attr("id") - 它应该返回 result.
一般来说，这个答案取决于 #result 是否是顶级元素.
如果#result是顶级元素，
<div id="结果"><span>文本</span></div><div id="其他顶级元素"></div>find() 将不起作用.相反，使用 filter():
var $result = $(response).filter('#result');如果#result不是顶级元素，
<div id="结果"><span>文本</span></div></div>find() 会起作用:
var $result = $(response).find('#result');
Trying to find div element with id="result" in returned data from .ajax() using .find(). Unfortunately, alert(result) doesn't return div#result.
Here is my code:
$.ajax({
url: url,
cache: false,
success: function(response) {
result = $(response).find("#result");
alert(response); // works as expected (returns all html)
alert(result); // returns [object Object]
}
});
解决方案 To answer your question specifically, it seems to be working correctly. You said that it returns [object Object], which is what jQuery will return with the find("#result") method. It returns a jQuery element that matches the find query.
Try getting an attribute of that object, like result.attr("id") - it should return result.
In general, this answer depends on whether or not #result is the top level element.
If #result is the top level element,
<!-- #result as top level element -->
<div id="result">
<span>Text</span>
</div>
<div id="other-top-level-element"></div>
find() will not work. Instead, use filter():
var $result = $(response).filter('#result');
If #result is not the top level element,
<!-- #result not as top level element -->
<div>
<div id="result">
<span>Text</span>
</div>
</div>
find() will work:
var $result = $(response).find('#result');
这篇关于来自 .ajax() 调用的数据的 jQuery .find() 正在返回“[object Object]".而不是 div的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持跟版网！
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