问题描述
我正在尝试编写密码验证器.
I'm trying to write a password validator.
如何查看我提供的字符串是否包含至少 3 个不同的字符组?
How can I see if my supplied string contains at least 3 different character groups?
检查它们是否存在很容易——但至少有 3 个?
It's easy enough to check if they are existant or not ---but at least 3?
至少八 (8) 个字符
at least eight (8) characters
至少三个不同的字符组
大写字母
小写字母
数字
特殊字符 !@#$%&/=?_.,:;-
special characters !@#$%&/=?_.,:;-
(我正在使用 javascript 进行正则表达式)
(I'm using javascript for regex)
推荐答案
只是为了学习 - 这种要求是否可以在纯正则表达式中实现?
Just to learn - would this kind of requirement be possible to implement in pure regex?
这将使它成为一个相当难以阅读(并因此维护!)的解决方案,但它是:
That'd make it a rather hard to read (and therefor maintain!) solution, but here it is:
(?mx)
^
(
(?=.*[a-z])(?=.*[A-Z])(?=.*[0-9]) # must contain a-z, A-Z and 0-9
| # OR
(?=.*[a-z])(?=.*[A-Z])(?=.*[!@#$%&/=?_.,:;\-]) # must contain a-z, A-Z and special
| # OR
(?=.*[a-z])(?=.*[0-9])(?=.*[!@#$%&/=?_.,:;\-]) # must contain a-z, 0-9 and special
| # OR
(?=.*[A-Z])(?=.*[0-9])(?=.*[!@#$%&/=?_.,:;\-]) # must contain A-Z, 0-9 and special
)
.{8,} # at least 8 chars
$
一个(可怕的)Javascript 演示:
A (horrible) Javascript demo:
var pw = "aa$aa1aa";
if(pw.match(/^((?=.*[a-z])(?=.*[A-Z])(?=.*[0-9])|(?=.*[a-z])(?=.*[A-Z])(?=.*[!@#$%&/=?_.,:;\-])|(?=.*[a-z])(?=.*[0-9])(?=.*[!@#$%&/=?_.,:;\-])|(?=.*[A-Z])(?=.*[0-9])(?=.*[!@#$%&/=?_.,:;\-])).{8,}$/)) {
print('Okay!');
} else {
print('Fail...');
}
打印:Okay!
,正如您在 Ideone 上看到的那样.
prints: Okay!
, as you can see on Ideone.
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