问题描述
我试图让按钮在悬停在图像上时出现.以下作品:
I'm trying to get buttons to appear when hovering over an image. The following works:
jQuery('.show-image').mouseenter(function() {
jQuery('.the-buttons').animate({
opacity: 1
}, 1500);
}).mouseout(function() {
jQuery('.the-buttons').animate({
opacity: 0
}, 1500);
});
但是,当从图像移动到按钮(在图像上方)时,会触发 mouseout/mouseenter,因此按钮会淡出然后淡入(按钮与图像具有相同的类,否则它们只是保持淡出).我怎样才能防止这种情况触发?我还使用 jQuery 的悬停尝试了上面的代码;相同的结果.这是显示不透明度为 1 的按钮的图像的详细信息(因为我在图像上方):
However, when moving from the image to the button (which is over the image), the mouseout/mouseenter is triggered, so the buttons fade out then fade back in (the buttons have the same class as the image, otherwise they just stay faded out). How can I prevent this from triggering? I've also tried the above code using jQuery's hover; same results. Here's a detail of the image showing the button with opacity 1 (because I'm over the image):
http://i.stack.imgur.com/egeVq.png
提前感谢您的任何建议.
Thanks in advance for any suggestions.
推荐答案
最简单的解决方案是将两者放在同一个父div
中,并给父div
show-image
类.
The simplest solution is to put the two in the same parent div
and give the parent div
the show-image
class.
我喜欢使用.hover()
以节省一些击键.(所有悬停都是实现 .mouseenter()
和 .mouseleave()
,但您不必输入它们)
I like to use .hover()
to save a few key strokes. (alll hover does is implement .mouseenter()
and .mouseleave()
, but you don't have to type them out)
此外,淡出 $(this).find(".the-buttons")
非常重要,这样您就只能更改悬停在 div
上的按钮,否则您将更改整个页面上的所有 .the-buttons
!.find()
只是寻找后代.
Additionally it's very imporant to fade $(this).find(".the-buttons")
so that you only change the button in the hovered over div
otherwise you would change all of the .the-buttons
on the entire page! .find()
just looks for descendants.
最后,.animate()
可以,但为什么不直接使用 .fadeIn()
和 .fadeOut()
强>?
Finally, .animate()
will work, but why not just use .fadeIn()
and .fadeOut()
?
JS:
jQuery(function() { // <== Doc ready
jQuery(".the-buttons").hide(); // Initially hide all buttons
jQuery('.show-image').hover(function() {
jQuery(this).find('.the-buttons').fadeIn(1500); // use .find() !
}, function() {
jQuery(this).find('.the-buttons').fadeOut(1500); // use .find() !
});
});
试试这个 jsFiddle
HTML: - 像这样的
Try it out with this jsFiddle
HTML: - Something like this
<div class="show-image">
<img src="http://i.stack.imgur.com/egeVq.png" />
<input class="the-buttons" type="button" value=" Click " />
</div>
CSS: - 像这样的东西.您的可能会有所不同.
CSS: - Something like this. Yours will likely be different.
div {
position: relative;
float:left;
margin:5px;}
div input {
position:absolute;
top:0;
left:0; }
这篇关于将鼠标悬停在图像上以显示按钮,并且在悬停在实际按钮上时不触发的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持跟版网!