问题描述
给定两个 Date() 对象，其中一个小于另一个，我如何在日期之间每天循环?
Given two Date() objects, where one is less than the other, how do I loop every day between the dates?
for(loopDate = startDate; loopDate < endDate; loopDate += 1)
{
}
这种循环行得通吗?但是我怎样才能在循环计数器中增加一天呢?
Would this sort of loop work? But how can I add one day to the loop counter?
谢谢！
推荐答案
这里有一种方法，通过使用添加一天导致日期在必要时滚动到下个月的方式来实现，并且不会乱用毫秒.夏令时也不是问题.
Here's a way to do it by making use of the way adding one day causes the date to roll over to the next month if necessary, and without messing around with milliseconds. Daylight savings aren't an issue either.
var now = new Date();
var daysOfYear = [];
for (var d = new Date(2012, 0, 1); d <= now; d.setDate(d.getDate() + 1)) {
daysOfYear.push(new Date(d));
}
请注意，如果您想存储日期，则需要创建一个新日期(如上使用 new Date(d))，否则您将结束每个存储的日期都是循环中 d 的最终值.
Note that if you want to store the date, you'll need to make a new one (as above with new Date(d)), or else you'll end up with every stored date being the final value of d in the loop.
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