问题描述
当我运行我的 (C++) 程序时,它会因为这个错误而崩溃.
When I run my (C++) program it crashes with this error.
* glibc 检测到 * ./load: double free or corruption (!prev):0x0000000000c6ed50 ***
* glibc detected * ./load: double free or corruption (!prev): 0x0000000000c6ed50 ***
如何追踪错误?
我尝试使用打印 (std::cout
) 语句,但没有成功.gdb
能让这更容易吗?
I tried using print (std::cout
) statements, without success. Could gdb
make this easier?
推荐答案
如果你使用 glibc,你可以将 MALLOC_CHECK_
环境变量设置为 2
,这将导致 glibc 使用 malloc
的容错版本,这将导致您的程序在双释放完成时中止.
If you're using glibc, you can set the MALLOC_CHECK_
environment variable to 2
, this will cause glibc to use an error tolerant version of malloc
, which will cause your program to abort at the point where the double free is done.
您可以在运行程序之前使用 set environment MALLOC_CHECK_2
命令从 gdb 设置它;程序应该中止,free()
调用在回溯中可见.
You can set this from gdb by using the set environment MALLOC_CHECK_ 2
command before running your program; the program should abort, with the free()
call visible in the backtrace.
请参阅 malloc()
的手册页,了解更多信息
see the man page for malloc()
for more information
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