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        是否可以将友元函数声明为静态函数?

        Is it possible to declare a friend function as static?(是否可以将友元函数声明为静态函数?)

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                  本文介绍了是否可以将友元函数声明为静态函数?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着跟版网的小编来一起学习吧!

                  问题描述

                  这里是一些编译和工作正常的 C++ 示例代码:

                  Here is some C++ example code that compiles and works fine:

                  class A
                  {
                  public:
                     A() {/* empty *
                                  
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