问题描述
我遇到了一个代码片段
const int& reference_to_const_int = 20;
cout<<"
reference_to_const_int = "<<reference_to_const_int<<endl;
此代码编译 &执行输出:-
This code compiles & executes with output :-
reference_to_const_int = 20
这对我来说很奇怪.据我所知参考不占用内存 &它们是其他变量的别名.因此我们不能说
This is something strange in for me. As I know reference do not occupy memory & they are aliases to other variables. hence we cannot say
int& reference_to_int = 30;
以上语句不能编译给出错误:-
The above statement shall not compile giving error :-
error: invalid initialization of non-const reference of type ‘int&’ from an rvalue of type ‘int’
const int&"究竟发生了什么案件?需要完整的解释.
What exactly is happening in the "const int&" case? A full explanation is desired.
请帮忙.
谢谢
推荐答案
创建了一个临时对象，将 const 引用绑定到它是合法的，但将它绑定到非 const 引用是非法的code>const 一.
A temporary is created, and it's legal to bind a const reference to it, but illegal to bind it to a non-const one.
就像:
const int& reference_to_const_int = int(20); //LEGAL
int& reference_to_const_int = int(20); //ILLEGAL
const 引用延长了临时文件的生命周期，这就是它起作用的原因.这只是语言的规则.
A const reference extends the life of a temporary, that's why this works. It's just a rule of the language.
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