问题描述

使用

<System.ComponentModel.TypeConverter(GetType(System.ComponentModel.ExpandableObjectConverter))> _

关于一个类的声明(它是另一个类的属性)，它由一个数字属性组成.

on the declaration of a class (which is a property of another class) that consists of a number properties.

我只用 ... 加载这个类的一个实例

I load an instance of this class with simply ...

PropertyGrid1.SelectedObject = oColumn

显然我不想在代码中手动构建 propertygrid，我知道该怎么做.

Obviously I don't want to manually build the propertygrid in code, I know how to do that.

但这就是问题所在.根据属性的值，某些其他属性不应该是可见的，就好像我使用了

But here's the problem. Depending on the value of a property, certain other properties should not be visible, as though I'd used the

<System.ComponentModel.Browsable(False)> _

属性声明.

有没有办法以编程方式执行此操作，而无需手动处理属性网格的所有构建>

Is there anyway to do this programmatically, without having to handle all the building of the property grid manually>

推荐答案

如果您希望使用 gridItem.Hide()，那么答案是否定的.在 MS PropertyGrid 中实现这一点的唯一方法是通过 TypeConverter 或自定义类型描述符(实现 ICustomTypeDescriptor)的 GetProperties 方法动态发布您的属性.我会先尝试使用 TypeConverter(特别是如果您要检查的属性值处于同一级别)，需要做的编码更少.

if you were hoping for a gridItem.Hide() then, the answer is no. The only way to achieve that in the MS PropertyGrid is to dynamically publish your properties through the GetProperties method of a TypeConverter or custom type descriptor (that implements ICustomTypeDescriptor). I would try first with the TypeConverter (expecially if the property values you want to check are at the same level), there is less coding to do.

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