更改表以根据 Order By 添加 Identity 列

Alter table to add Identity column based on Order By(更改表以根据 Order By 添加 Identity 列)
本文介绍了更改表以根据 Order By 添加 Identity 列的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着跟版网的小编来一起学习吧!

问题描述

我有这张桌子

------------------------------------
| **Id**  |**Name**  | **Created** | 
------------------------------------
| Guid1   | John Doe |  2016-01-01 |
------------------------------------
| Guid2   | Mary Jane|  2015-01-01 |
------------------------------------

列 ID 是 PK 和聚集索引,所以我想添加一个标识列:

Column Id is the PK and a Clustered Index, so I want to add an Identity Column:

ALTER TABLE [Person]
ADD
IdentityCol INT IDENTITY(1,1) NOT NULL

问题是,每次我尝试这样做时,它都会根据表的默认顺序添加 IdentityCol 的值,我认为它是由列 Id 定义的

The problem is that every time when I try to do this, it adds the value of IdentityCol, based on the default order of the table, which I suppose is defined by the column Id

-------------------------------------------------
| **Id**  |**Name**  | **Created** | IdentityCol|
-------------------------------------------------
| Guid1   | John Doe |  2016-01-01 |    1       |
-------------------------------------------------
| Guid2   | Mary Jane|  2015-01-01 |    2       |
-------------------------------------------------

购买我想要的是按创建列创建值顺序

Buy what I want is that create the values order by Created column

-------------------------------------------------
| **Id**  |**Name**  | **Created** | IdentityCol|
-------------------------------------------------
| Guid1   | John Doe |  2016-01-01 |    2       |
-------------------------------------------------
| Guid2   | Mary Jane|  2015-01-01 |    1       |
-------------------------------------------------

有什么办法可以在 ALTER 语句中指定 Order By 吗?

Is there any way to specify the Order By in ALTER sentence?

推荐答案

使用行号:

UPDATE Person p
SET IdentityCol = (SELECT ROW_NUMBER() over (ORDER BY Created) AS rn
                   FROM Person t WHERE p.Id = t.Id)

然后您可以通过以下方式将 IdentityCol 设置为正式身份列:

Then you could set the IdentityCol as a formal identity column via:

SET IDENTITY_INSERT database.schema.Person ON

这篇关于更改表以根据 Order By 添加 Identity 列的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持跟版网!

本站部分内容来源互联网,如果有图片或者内容侵犯您的权益请联系我们删除!

相关文档推荐

Number of working days between two dates(两个日期之间的工作日数)
How do I use dateadd to get the first day of last year?(如何使用 dateadd 获取去年的第一天?)
SQL- Count occurrences of a specific word within all stored procedures(SQL- 计算所有存储过程中特定单词的出现次数)
SQL query to make a column of numbers a string(使一列数字成为字符串的 SQL 查询)
T-SQL: Best way to replace NULL with most recent non-null value?(T-SQL:用最新的非空值替换 NULL 的最佳方法?)
Count days in date range with set of exclusions which may overlap(使用一组可能重叠的排除项计算日期范围内的天数)