问题描述
我在以下代码中收到java.lang.IllegalArgumentException: bad base-64":
I'm getting a "java.lang.IllegalArgumentException: bad base-64" on the following code:
byte[] msgBytes = Base64.decode(msgStr, Base64.NO_WRAP);
msgString 是一个字符串，就在这一行之前，我检查了 msgStr 的值，它是fl-ILw==".有什么问题吗?
msgString is a String, and right before this line, I check the value of msgStr and it is "fl-ILw==". Is there anything wrong?
谢谢.
推荐答案
根据 RFC 4648(http://www.rfc-editor.org/rfc/rfc4648.txt) '-' 字符不是有效的 Base64 字符，但另一方面对URL 和文件名安全的 Base 64 字母"有效.
According to RFC 4648(http://www.rfc-editor.org/rfc/rfc4648.txt) '-' character is not a valid Base64 character but on the other hand is valid for "URL and Filename safe Base 64 Alphabet".
因此您可以根据字符串的预期格式使用 Base64.URL_SAFE.
So you could use Base64.URL_SAFE depending of the expected format of the string.
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