问题描述
我正在尝试在 python 中创建一个创建自定义 python 对象的 yaml 序列.对象需要用 __init__ 之后解构的字典和列表来构造.但是，construct_mapping 函数似乎并没有构建嵌入序列(列表)和字典的整个树.
考虑以下几点:
I am trying to make a yaml sequence in python that creates a custom python object. The object needs to be constructed with dicts and lists that are deconstructed after __init__. However, it seems that the construct_mapping function does not construct the entire tree of embedded sequences (lists) and dicts.
Consider the following:
import yaml
class Foo(object):
def __init__(self, s, l=None, d=None):
self.s = s
self.l = l
self.d = d
def foo_constructor(loader, node):
values = loader.construct_mapping(node)
s = values["s"]
d = values["d"]
l = values["l"]
return Foo(s, d, l)
yaml.add_constructor(u'!Foo', foo_constructor)
f = yaml.load('''
--- !Foo
s: 1
l: [1, 2]
d: {try: this}''')
print(f)
# prints: 'Foo(1, {'try': 'this'}, [1, 2])'
这很好用，因为 f 包含对 l 和 d 对象的引用，这些对象实际上在 after<之后填充了数据/strong> Foo 对象已创建.
This works fine because f holds the references to the l and d objects, which are actually filled with data after the Foo object is created.
现在，让我们做一些更复杂的事情:
Now, let's do something a smidgen more complicated:
class Foo(object):
def __init__(self, s, l=None, d=None):
self.s = s
# assume two-value list for l
self.l1, self.l2 = l
self.d = d
现在我们得到以下错误
Traceback (most recent call last):
File "test.py", line 27, in <module>
d: {try: this}''')
File "/opt/homebrew/lib/python2.7/site-packages/yaml/__init__.py", line 71, in load
return loader.get_single_data()
File "/opt/homebrew/lib/python2.7/site-packages/yaml/constructor.py", line 39, in get_single_data
return self.construct_document(node)
File "/opt/homebrew/lib/python2.7/site-packages/yaml/constructor.py", line 43, in construct_document
data = self.construct_object(node)
File "/opt/homebrew/lib/python2.7/site-packages/yaml/constructor.py", line 88, in construct_object
data = constructor(self, node)
File "test.py", line 19, in foo_constructor
return Foo(s, d, l)
File "test.py", line 7, in __init__
self.l1, self.l2 = l
ValueError: need more than 0 values to unpack
这是因为yaml构造函数是在嵌套before的外层开始，在所有节点完成之前构造对象.有没有办法颠倒顺序并首先从深度嵌入(例如嵌套)对象开始?或者，有没有办法让构造至少在节点的对象被加载之后发生?
This is because the yaml constructor is starting at the outer layer of nesting before and constructing the object before all nodes are finished. Is there a way to reverse the order and start with deeply embedded (e.g. nested) objects first? Alternatively, is there a way to get construction to happen at least after the node's objects have been loaded?
推荐答案
好吧，你知道什么.我找到的解决方案非常简单，但文档却没有那么完善.
Well, what do you know. The solution I found was so simple, yet not so well documented.
Loader 类文档清楚地表明 construct_mapping 方法只需要在单个参数(node)中.但是，在考虑编写自己的构造函数后，我查看了源代码，答案是 就在那里！该方法还接受一个参数deep(默认为False).
The Loader class documentation clearly shows the construct_mapping method only takes in a single parameter (node). However, after considering writing my own constructor, I checked out the source, and the answer was right there! The method also takes in a parameter deep (default False).
def construct_mapping(self, node, deep=False):
#...
所以，正确使用的构造方法是
So, the correct constructor method to use is
def foo_constructor(loader, node):
values = loader.construct_mapping(node, deep=True)
#...
我猜 PyYaml 可以使用一些额外的文档，但我很感激它已经存在.
I guess PyYaml could use some additional documentation, but I'm grateful that it already exists.
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