问题描述
我正在编写一个不和谐的机器人,在尝试使用命令 !members in on_message 事件从服务器中提取所有成员时遇到此错误:
I am writing a discord bot and I came across this error when trying to pull all the members from a server with the command !members in on_message event:
elif message.content.startswith('!members'):
x = server.Server.members
for member in x:
print(member)
我希望这个命令拉出所有成员并在控制台中打印出来,但我得到了错误
I want this command to pull all members and print them out in the console but I get the error
TypeError: 'property' 对象不可迭代
TypeError: 'property' object is not iterable
当我在不和谐频道中输入命令时.谁能帮我列出频道中所有成员的列表以供进一步使用?
when I type the command in the discord channel. Could anyone help me make a list of all members in the channel that I can have for further use?
推荐答案
你需要一个服务器实例来从中获取成员列表.
You need an instance of a server to get the members list from it.
假设此代码出现在 on_message(message)
中,您应该可以更改您的
Assuming this code appears in on_message(message)
, you should be able to change your
x = server.Server.members
到
x = message.server.members
请注意,使用带有大写 S 的 Server
将返回类定义,而使用消息中的 server
属性(小写 s)将检索 Server 的实例.
Note that using Server
with a capital S will return the class definition, whereas using the server
property (lowercase s) from the message will retrieve an instance of Server.
如果您使用的版本 >= 1.0.0,则为
If you're using a version >= 1.0.0, this will be
x = message.guild.members
改为.
这篇关于如何使用 discord.py 列出不和谐服务器中的所有成员?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持跟版网!