本文介绍了Python 的 CSV 阅读器和迭代的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着跟版网的小编来一起学习吧!
问题描述
I have a CSV file that looks like this:
"Company, Inc.",,,,,,,,,,,,10/30/09
A/R Summary Aged Analysis Report,,,,,,,,,,,,10:35:01
All Clients,,,,,,,,,,,,USER
Client Account,Customer Name,15-Jan,16 - 30,31 - 60,61 - 90,91 - 120,120 - Over,Total,Status,Credit Limit
1000001111,CLIENT A,0,0,"3,711.32",0,0,"18,629.64","22,340.96",COD,"20,000.00"
1000002222,CLIENT B,0,0,0,"3,591.27",0,0,"3,591.27",COD,0
1000003333,CLIENT C,536.78,0,0,0,0,"11,216.60","11,753.38",COD,0
1000004444,CLIENT D,0,514.94,"3,147.45",690,0,0,"4,352.39",COD,0
Grand Total,,"139,203,856.06","84,607,749.30","110,746,640.18","58,474,379.45","52,025,869.06","292,653,734.82","737,712,228.87",,,,
But I only want to process the lines after the line "Client Account..." and before "Grand Total..." Here's the code that I'm using now:
inputFile = csv.reader(open(filename), dialect='excel')
records = [line for line in inputFile if line and line[0].isdigit()]
解决方案
Via generators. You can build all kinds of complexity from simple generator-filter functions. While considerably more complex than your filter, this is more extensible and can easily handle really complex spreadsheets.
def skip_blank( rdr ):
for row in rdr:
if len(row) == 0: continue
if all(len(col)==0 for col in row): continue
yield row
def after_heading( text, rdr ):
i= iter(rdr)
for row in i:
if any( column == text for column in row ):
break
for row in i:
yield row
def before_footing( text, rdr ):
for row in rdr:
if any( column == text for column in row ):
break
yield row
def between( start, end, rdr ):
for row in before_footing( end, after_heading( start, rdr ) ):
yield row
for row in between( 'Grand Total', 'Client Account', skip_blank( inputFile ) ):
print row
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