本文介绍了为列中的每一行生成 guid的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着跟版网的小编来一起学习吧!
问题描述
我有一个包含一列表的存储过程,我需要为该列中的每一行生成一个 NEWID().我只能通过循环来完成此操作吗?
I Have a stored procedure that has a table with one column and I need to generate a NEWID() for each row in that column. Would I only be able to accomplish this with a loop?
+---+ +--------------------------------------+---+
| a | | FD16A8B5-DBE6-46AB-A59A-6B6674E9A78D | a |
| b | => | 9E4A6EE6-1C95-4C7F-A666-F88B32D24B59 | b |
| c | | 468C0B23-5A7E-404E-A9CB-F624BDA476DA | c |
+---+ +--------------------------------------+---+
推荐答案
您应该能够从表中进行选择并包含 newid()
以生成每一行的值:
You should be able to select from your table and include the newid()
to generate the value for each row:
select newid(), col
from yourtable;
参见SQL Fiddle with Demo
这篇关于为列中的每一行生成 guid的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持跟版网!
本站部分内容来源互联网,如果有图片或者内容侵犯您的权益请联系我们删除!