问题描述
我有一个普通的 df.index，我想增加几个小时.
I have a normal df.index that I would like to add some hours to it.
In [1]: test[1].index
Out[2]:
<class 'pandas.tseries.index.DatetimeIndex'>
[2010-03-11, ..., 2014-08-14]
Length: 52, Freq: None, Timezone: None
这是第一个元素的样子:
This is how the first element looks like:
In [1]: test[1].index[0]
Out[2]: Timestamp('2010-03-11 00:00:00')
所以我试试这个来增加时间:
So I try this to add the hours:
In [1]: test[1].index[0] + pd.tseries.timedeltas.to_timedelta(16, unit='h')
但是我明白了:
Out[2]: Timestamp('2010-03-11 00:00:00.000000016')
但我想得到这个:
Out[2]: Timestamp('2010-03-11 16:00:00')
我错过了什么?环境是 Anaconda (latest) Python 2.7.7, iPython 2.2
What I am missing?. The enviroment is Anaconda (latest) Python 2.7.7, iPython 2.2
非常感谢
推荐答案
你可以使用pd.DateOffset:
test[1].index + pd.DateOffset(hours=16)
pd.DateOffset 接受与 dateutil.relativedelta 相同的关键字参数.
pd.DateOffset accepts the same keyword arguments as dateutil.relativedelta.
您遇到的问题是由于此错误，该错误已在 Pandas 版本 0.14.1 中修复:
The problem you encountered was due to this bug which has been fixed in Pandas version 0.14.1:
In [242]: pd.to_timedelta(16, unit='h')
Out[242]: numpy.timedelta64(16,'ns')
如果您升级，您的原始代码应该可以工作.
If you upgrade, your original code should work.
这篇关于如何正确地将小时数添加到 pandas.tseries.index.DatetimeIndex?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持跟版网！